This post is shared by iOS developers India who tell you the best way to integrate TouchID authentication or passwordless authentication into your iPad or iPhone application. Learn from this tutorial and share your experience at the end in comments.
One-liner: In this tutorial, we will learn about how to integrate touchID authentication or passwordless authentication into your iPhone or iPad application.
Start with creating one single view application with the name “TouchIDDemo”. Select swift as the development language and make it universal. Add LocalAuthentication.framework after creating the project.
Open the Main.storyboard file and add one button in the middle of the main view and set title “Authentication”. Add one navigation controller with a storyboard entry point and connect with the main view as a “root view controller”. Please check below screenshot for more info.
In ViewController.swift file, import LocalAuthentication framework. Create an IBAction method btnAuthenticationClick that connected with the Authentication button. In this method first, we need to create an instance of the LAContext class. As all devices do not support TouchID sensor so, we need to check that a fingerprint sensor is available on a device or not, for that we call canEvaluatePolicy() method. If the device has, no TouchID sensor than show appropriate error alert. If the device has a TouchID sensor, we show the user a typical TouchID form.
Next method is with three argument like evaluatePolicy:localizedReason:reply(). In this method, we get whether the fingerprint is recognized or not. Please check below screenshot for more info.
Add a method named showAlertWithTitle() for showing alert messages to the user in case of error.
Add a method named errorMessageForLAErrorCode() for returning error message using error code we receive in reply method by comparing the error code with LAError class. Please check below screenshot for more info.
Build and run the project. If everything is correct, your app will let you authenticate using touchID.
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